$x^2\:+\:5x\:+\:4$
$\frac{b}{h}=\frac{2}{\sqrt{3}}$
$\frac{d}{dx}\left(x^{2\arctan\left(3x\right)}\right)$
$3x+5\ge4x-1$
$2\sin^2\left(x\right)-3\cos\left(x\right)$
$4+\:-1\:+\:-1\:+\:-12$
$\left(a^{-4}b^{-3}\right)\left(a^3b^{-4}\right)$
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