$x^2-16x=-40$
$\frac{\sin\:^2\left(x\right)+\cos\:^2\left(x\right)}{sin\left(x\right)cos\left(x\right)}$
$\lim_{x\to0}\left(\frac{9^x-8^x}{3^x-2^x}\right)$
$3\left(-1\right)^2+4$
$m^2+2m+5$
$\lim_{x\to\pi}\left(\frac{x^2-3x}{\sin\left(x\right)}\right)$
$5\left(x-2\right)+8=5x-1$
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