$\left(132\left(\frac{1}{11}z^8-\frac{1}{12}\right)\right)^2$
$4x^2y^5+5xy^7$
$x+5=14$
$cos^2\theta\:\left(tan^2\theta\:\:+1\right)=1$
$ln\left(x^2\right)=ln^2\left(x\right)$
$\frac{dy}{dx}=3x^2+\frac{c}{x^4}$
$8+7-11.3-2.8+6-18-9+3$
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