$\frac{sin^4x-cos^4x}{sin^2x}=2csc^2x$
$x\left(x^3+3x\right)$
$\frac{243x^5-32}{3x+2}$
$\frac{5}{4x}+\frac{1}{x}=\frac{3}{x-5}$
$x^2+7x+y^2=11$
$\int\left(3\left(ax^3+b\right)\right)dx$
$\left(m+5\right)\left(m-6\right)$
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