$5\tan\left(x\right)+4=4-\tan\left(x\right)$
$\frac{x}{1-x}\ge2$
$x\sqrt{y}\left(-x\sqrt{y}\right)$
$\:120-5.5$
$8.6+4.5$
$\frac{\left(10x\:+12\:-\:2x^3\:-\:4x^2\right)}{\left(x-1\right)}$
$y'\:-\frac{2y}{x+1}=\left(x+1\right)^3$
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