$\lim_{x\to0}\left(\frac{-e^x+1}{xe^x}\right)$
$-3\cdot35$
$\int x^2\left(3x^3-5\right)^{\frac{3}{4}}dx$
$\frac{3.14}{2}$
$\left(x+6\right)\left(2x^2-5x+7\right)$
$\frac{3\left(x^2+2\right)^3}{5}$
$6x^2-4x-2$
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