$\frac{d}{dx}2\sin x+3\cos x$
$-7\:x\:3\:x\:-5$
$5.4\cdot10^6$
$-200+\left(\left(-\frac{32}{2}\right)-\left(-\frac{15}{5}\right)+\left(-15\right)\right)$
$\int\left(6x+4\right)\left(x-5\right)^2dx$
$-14-\left(-6\right)-9$
$- \frac { 9 x } { 3 x ^ { 2 } }$
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