$\frac{x^2}{9}\:+\frac{2xy}{3}\:-\:y^2$
$y=-3,z=7$
$9x^2+48x-64$
$y^5y'=t\:cost$
$\left(x^2-1\right)dy=-2xydx$
$\frac{x+5y}{2}+\frac{3x+5y}{3}$
$\left(x^2+5x\right).\left(x^2-5x\right)$
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