$\frac{x+5}{4}+\frac{x-3}{2}>5$
$x^2-7x+3=0$
$\frac{sin^2\left(x\right)-4}{sin^2\left(x\right)-2sin\left(x\right)}$
$x^{2}-3x-28$
$\sqrt[3]{-8}\sqrt[3]{-27}$
$\left(2+5\right)^2+1$
$\frac{2^3x^3y^4}{2xy^2z}$
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