$-\frac{1}{2}\cdot16$
$9a^212ab+4b^2$
$-13-\left(+21\right)+73-\left(-48\right)-29$
$-5m^ab^{n-1}\:.-7m^{29-3}n^{b-4}$
$\lim_{x\to\infty}\left(2x-\frac{1}{x^2}\right)$
$\frac{d}{dx}senx^2\:lnx$
$\sqrt{32^{3\sqrt{a^9b^8}}}$
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