$2\frac{dy}{dx}+5x=6$
$\frac{d}{dx}-4y^2-9=0$
$\int\:3x^3e^{-4x}dx$
$-28-\left(-40\right)$
$8\:+\:x\:=\:14$
$\lim_{x\to\infty}\left(\frac{2x^3-1}{x^3+5x+4}\right)$
$\frac{\frac{4}{c-3}-\frac{2}{c+2}}{\frac{8}{c^2+6c+8}}$
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