$x^2-29x-44=0$
$\frac{2x^3-2-4}{2+2x}$
$\lim_{n\to\infty}\left(\frac{n+2}{n^2-4}\right)$
$\lim\:_{x\to\:\frac{\pi\:}{3}}\left(\frac{\tan\:\left(5x\right)}{\tan\:\left(3x\right)}\right)$
$x2\:-\:3x\:\ge\:2x$
$\frac{10x+1}{\left(2x+1\right)^2}$
$y=\sin5\cdot$
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