$8a^3b^3\:2a-b$
$-19-2\cdot\left(-2\right)$
$\sqrt{x}\sqrt{y}\cdot\:\:2\sqrt{3}x^6y$
$\left(x-1\right)dy+4ydx=0$
$\frac{\left(\left(5x-2\right)^3\left(8x+1\right)\right)}{\left(4x+2\right)^2}$
$\left(a^2-b\right)^4$
$-2x\:x\:2y$
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