$\sqrt{16}+9+\left(2+3\right)^3$
$\left(3x^2+10xy\right)dx\:+\:5x^2dy=0$
$6\left(2b-3\right)=2\left(5b+9\right)$
$\frac{dy}{dx}-4=0.8$
$3sinx=sinx+1$
$\frac{dy}{dx}=\frac{4x^3y}{y^4+y^2}$
$\int\frac{arcsecx}{\sqrt{x^2-1}}dx$
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