$x^2+5x+19;\:x=3$
$\frac{1}{2}x-6=\frac{1}{5}x$
$\int\frac{8x^3}{2x^4+5x}dx$
$\int4sen^2x\:dx$
$2x^3vm-4x^2n+x^2v^2n$
$\lim_{x\to\infty}\left(1-\frac{6}{x+3}\right)^{4x}$
$\lim_{x\to0}\left(\ln\left(1+x\right)\right)^{\frac{x}{\ln\left(x\right)}}$
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