$\left(2m^2-n^2\right)\left(2m^2+n^2\right)$
$8m^3+16m^2n$
$3,45\:x\:2,34$
$\tan x^2=1$
$-2\le x$
$\left(4-5\right)\:.\:\left(-3\right)-\:\left(8-2\right)\::\:\left(-3\right)$
$4x^2+6=10x$
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