$y=x^5+2x^{-3}\:$
$3x^3-x^2-18x+6$
$6x-12=-6$
$\left[\left(-7\right)-\left(+4\right)\right]\cdot\left(+6\right)$
$\frac{7}{3}x+2\ge-1$
$\frac{tan\left(t\right)+cot\left(t\right)}{sec^2\left(t\right)}$
$-x^2+12x^3-4x$
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