$-7x=-7$
$\int\frac{1}{x^2-8x+16}dx$
$\frac{dy}{dx}=\frac{\sin\left(x\right)}{x^2}$
$\left(\sqrt{3}+\sqrt{3}\right)^8$
$\left(8b^6+k\right)^3$
$\left(12x+16\right)\left(6x+4\right)$
$\frac{tanx+tany}{1-tanx\:tany}$
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