$3x-4\le x+8$
$\int_0^1\left(x^2+2e^x-4\right)dx$
$x\frac{dy}{dx}+6y=18$
$10\left(y+2\right)$
$\left(2\sqrt{y-3}\right)\left(2\sqrt{y+3}\right)$
$\int\frac{120}{t^3+2t^2-15t}dx$
$\frac{x^2+2}{x+1}>x$
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