$\frac{1}{\left(cosx+1\right)\left(cosx-1\right)}=\frac{1}{tan^2x.sin^2x}$
$\frac{x^3}{x^{-2}}^2$
$\sin\left(2x\right)=1-\cos\left(4x\right)$
$4\cdot\:4\cdot\:4$
$-2n-3n$
$x+3>3x-2$
$10c^3-80^3-5c^6+5c^7$
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