$2x^2-2x-4\le0$
$x^2+3x=18$
$\lim_{x\to-3}\left(\frac{x^2+4x+3}{x^2-3}\right)$
$-63+-60+-16$
$7\:x\:2\:-\:20\:x\:-\:3$
$\int4.02\cdot\left(e^{\left(-4.02x\right)}\right)$
$81xy\:and\:\left(9^2\right)xy$
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