$3x+2x^2-\frac{3}{8}\left(16x-3\right)-4x^2$
$cos^2x=0.6$
$\lim_{x\to1}\frac{lnx}{5x-2x^2-4}$
$\frac{x^4+2}{x^2+4x+5}$
$15x\ge\:\:-5$
$-24.37+5.309$
$29x+10x^2+10$
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