$\frac{d}{dx}x^2y+9=y^2+3x$

$2cos\left(3\:\theta\:\right)\:=\:-\sqrt{2}$

$3x+5\le4x-2$

$4x^2-6x<6x-9$

$\left(10x^6-20\right)\left(10x^6+25\right)$

$\int\left(\frac{2a}{\sqrt{x}}-\frac{b}{x^{2}}+3c\sqrt{x^{2}}\right)dx$

$\frac{\sin\left(3x\right)\cos\left(x\right)-\sin\left(x\right)\cos\left(3x\right)}{\sin\left(2x\right)}=1$