$\frac{24a^4b^5+18a^2b^3}{-3a^2b^4}$

$\frac{1}{3}\left(0\right)-2\left(0\right)^2+6\left(0\right)+8$

$\int\left(2x\left(x+4\right)^2\right)dx$

$3x+4y+2x+4y$

$\left(\cos\left(x\right)-\csc\left(x\right)\right)\left(\cos\left(x\right)+1\right)$

$\frac{5}{x-3}+\frac{2}{x+3}=\frac{-x^2+17x-7}{x^2-9}$

$\left(\frac{1}{6}+4x^4\right)^3$