$-270\cdot8$
$\int\left(4\left(4x+1\right)\right)dx$
$3+2y-8+9-4y$
$y^2-16y+64$
$\frac{1}{2}\int\left(2\sin\left(x\right)\right)^2dx$
$\left(4a^2b^2+5x^4y^4\right)\left(4a^2b^2-5x^4y^4\right)$
$\frac{4x^2+16x+16}{x+3}$
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