$\left(\frac{1}{x}+3x\right)^2\left(5x-1\right)$
$3\:x+2\:y-\:\:\:z=12$
$\frac{3}{5x-6}\le\:-2$
$6^2+13x+5$
$x^2-20x+7$
$x^3+6x^22+12x+8$
$15x^2-14x+3$
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