$\left(x^3-3\right)\left(x^2+3\right)$
$y'=e^{\left(x+y\right)}$
$5a\left(3b^2+6c^5-d^2\right)$
$\:k\:6\:-\:h\:6\:$
$7q+2q-6q$
$7y-12\cdot7y-8$
$4\log_b\left(z\right)-\frac{1}{3}\log_b\left(y\right)+6\log_b\left(x\right)$
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