$\sqrt[3]{1.16739}$
$\left(11x^4+3y^2\right)^2$
$\frac { 4 } { \frac { 1 } { 3 } }$
$-3x^2+4x+1$
$-8-\left|-5+\left(-1+2-3\right)\right|+\left(4-1-8+2\right)+1$
$\lim_{x\to\infty}\left(\frac{2}{3}\right)^x$
$3^1\cdot3^5$
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