$\int_6^{6x^2}\left(\frac{3x^4}{\sqrt{x-4}}\right)dx$

$2x\left[2\right]+6x$

$\left(\frac{3}{5}xy^3-\frac{1}{4}z\right)\left(\frac{3}{5}xy^3+\frac{1}{4}z\right)$

$f^{-1}\left(n\right)=n\left(n+1\right)$

$12:\left(-2\right)$

$\int\left(\frac{3x}{x^2+1}\right)dx$

$\frac{df}{dx}=f^{2}x^{3}$