$\lim_{x\to\infty}\left(16x\right)^{\frac{\ln4+1}{\ln\left(12x\right)+1}}$

$\int\frac{1}{4+5\cos\left(x\right)}dx$

$\left(3+\cos\left(2x\right)\right)$

$\lim_{x\to0}\left(\frac{1+sinx}{\left(\arctan\left(x\right)\right)}-e^x\right)$

$\lim_{x\to0}\left(\frac{\sec^2\left(x\right)}{x^2}\right)$

$tan^{-1}\left(\frac{2}{3}\right)-\:tan^{-1}\left(\frac{x}{5}\right)=\:\frac{\pi}{4}$

$8x^2-16xy+16y^2$