$369^4-25b^4$
$4\cot x+2=6$
$\int\frac{1}{2+v^2}dv$
$\frac{4x+3}{2}+\frac{3x-4}{3}$
$\frac{dy}{dx}-x+y=0$
$\frac{p+19}{3}=4$
$\left(4b^{-2}\:c^2\right)^{-3}\:\left(2b^7\:c^{-3}\right)^3$
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