$\sqrt{-16}-\sqrt{-64}$

$\left(arctan\left(\frac{y}{x}\right)=\ln\left(x\right)+\ln\left(c\right)\right)$

$\lim_{x\to\infty}\left(\frac{\cos\left(4x\right)-\cos^2\left(2x\right)}{x}\right)$

$\frac{tan^2\left(x\right)}{\:sec\left(x\right)}=\frac{1-cos\left(x\right)}{cos\left(x\right)}$

$\left(3m+\:2v\right)^2$

$x^2-7x+10;\:x=2$

$3^{9z}=3^{7z+8}$