$\int\frac{2x^4+3x^3+x^2}{x^3}dx$
$h\left(t\right)=\left(t-\frac{1}{t}\right)^{\frac{3}{2}}$
$y\left(-1+3y^2-2y\right)$
$\left(4x-9\right)^3$
$-10x^6+16y^6$
$13-\left(-39\right)$
$\left(3x^2+6y^3\right)$
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