$\left(64x^2-18\right)$
$-9+8-1+4+3-2-9$
$105=x+2x^2$
$2\csc^2x-\csc x=1$
$11x+12^3\:$
$\left(-1\right)\cdot\left(-7\right)\cdot\left(4\right)\cdot\left(-5\right)$
$\lim_{x\to\infty}\left(\frac{x}{\frac{1}{sin\left(\frac{1}{x^2}\right)}}\right)$
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