$\left(\sqrt{13+4\sqrt{3}}\right)\left(\sqrt{13-4\sqrt{3}}\right)$
$x\left(2-y\right)+4\left(y-2\right)$
$\sqrt[3]{a^6b^{12}c^3}$
$x9\:\cdot\:x-7$
$x^2=x^2+x$
$\frac{d}{dx}6x^{-9\sqrt[3]{x}}$
$4-3\left(x-2\right)\ge2\left(x+3\right)$
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