$x^2-3x=2$
$\int_0^2\sqrt{x+y}dy$
$\left(10^2\right)^3$
$-2\cdot3+3$
$\frac{3x^2-x}{x^2-1}$
$\left(y+6\right)\left(y+10\right)$
$\frac{3x^2+8}{x}=\frac{8}{x}+3x$
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