$\frac{5x^4-3x^3+2x^2-7x-3}{x-1}$
$4x^2+6\le0$
$\cot\left(x\right)+3=4$
$\lim_{x\to\infty}\left(\log_e\left(\frac{x+0.000104}{x}\right)\right)$
$49m^2-14m+1$
$\left(x^2+1\right)^4$
$\cos x\left(1-\sin^2x\right)=\cos^3x$
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