$s^2+4s+13$
$12a-5b+\left(3a-2b\right)-\left(-8b-10\right)$
$2x-8<10+3x$
$17-x=6$
$\left(4z+3\right)\left(2z-5\right)$
$2m^{2}+6m$
$-\frac{1}{0^2}$
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