$\sqrt{2^4}$
$\frac{d}{dx}\left(7x\right)^{4x}$
$\frac{6x-18}{x^2-3x}$
$-0.1b=3.8$
$\left(7x\right)^2$
$\frac{dy}{dx}=\frac{1}{4}\left(y+1\right)\left(y-2\right)^2$
$\frac{6c^3-12c^2+3c}{-3c}$
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