$6x+8-6-8-9-4x$
$\left(-3x+y\right)\left(-2x-y\right)$
$m^2+16m=-59$
$\left(2x-4x^2\right)^3$
$\frac{\left(x^2-8x+7\right)}{x-2}$
$\lim_{x,y\to0,0}\left(\frac{x^2-y^2}{\left(x+y\right)^2}\right)$
$\int\:-8x^4\cos\left(4x^5\right)dx$
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