$\cos^2x\:+1=2$
$1,005\:=\:1,005^m$
$\int\:12\cos6x\:dx$
$logz+log2=3$
$\int\:\:\:t^2\:cos\:\left(1-t^3\right)dt$
$\int_2^3\left(\mathrm{sech}^2x\tanh^5\right)dx$
$\frac{d}{dx}\ln\left(\sqrt{7+x^3}\right)$
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