$\int\frac{x}{x^2-2x+3}dx$
$\left(x+10\right)^2=256$
$22=t+u$
$\left(x^2-5x-14\right)-\left(x-2\right)$
$xsen\left(\frac{\sqrt{15}}{4}\left(0\right)\right)$
$f\left(x\right)=3x^2-2x-5\:entre\:x+1$
$\int\:\frac{3x^3+5x}{x^2+1}dx$
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