$x^2-10x+20$
$1+5x=-29$
$\frac{10^7\cdot10^3}{10^{10}}$
$\left(5x-3y^2\right)\left(5x+3y^2\right)$
$\frac{\sec^2\left(2u\right)-1}{\sec^2\left(2u\right)}=1$
$\sqrt[6]{-16}$
$\sqrt{\left(x^2-2x-3\right)^2}\le\:5\sqrt{\left(x^2-4x-3\right)^2}$
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