$x^2-4x-1=0$
$( t + 5 ) ( t + 9 )$
$\lim_{x\to1}\left(\frac{x^2+3x-18}{x^2-1}\right)$
$10-2\left(11x-3\right)$
$5xy-y=9x+4y$
$\cot\left(25\right)\sec\left(25\right)\cos\left(55\right)$
$2x^2-9x+4$
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