$\left(x+\frac{3}{4}\right)\left(x-\frac{5}{4}\right)$
$\left(x^6\right)^7$
$8+2\cdot4-3$
$\frac{d}{dx}\left(7x^2-3\right)$
$9m^4-6m^4+1$
$\lim_{x\to0}\left(1-6x^2\right)^{\frac{1}{x}}$
$2a+b=40$
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