$\left(128-53\right):\left(-3-12\right)$
$\int\left(\frac{x+2}{\left(x-2\right)\left(x+3\right)}\right)dx$
$7+14-3\:x\:7+7\:x\:10$
$8x-3>7x+12$
$x^3+6x^2+4x$
$\int\left(x^4+3\right)^3dx$
$6-5\left(3\right)$
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