$2sin2\theta-1=0$
$1-343a^3$
$\lim_{x\to\infty}\left(\frac{6x^3+8x^2+1}{\left(x+8\right)\left(5x+1\right)}\right)$
$\:\frac{3x-8}{x^2-4x-5}$
$0.12x-0.85x$
$x^3+\:x^4tanx\:$
$15\:-\:\left(-\left(12\right)\right)$
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