$\frac{\left(4a^{2}b^{3}\right)^{2}}{\left(a^{3}b^{2}\right)^{5}}$
$2\cdot\left(-6\cdot x\right)$
$2tan^2x=2$
$7y^2-8y+8-13y^2-8y+4$
$\frac{d}{dx}\left(y^3+7xy+4x^3-7x=0\right)$
$\int_{1}^{x\sqrt{x+3}}dx$
$6x-8\ge1$
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