$\frac{dx}{dt}+sec^2\left(t\right)x=sec^2\left(t\right)$
$f\left(x\right)=\ln\left(6x^3-10x^5\right)$
$\left(-2\right)^3\cdot\left(-2\right)^4\cdot\left(-2\right)^5$
$\frac{dy}{dx}=2xln\left(x\right)$
$-4+4\left(-2+7\left(-5\right)\right)$
$1+x+5-9xb+6x-3+12xb$
$e^{x+1}y=x$
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