$\tan^2x+5=\sec^2x+4$
$9m^{10}-42m^5n^3+49n^6$
$15ab^3\cdot\left(-4ab^4\right)$
$x^2+2x-10$
$\left(+2\right)\cdot\left(+4\right)\cdot\left(-8\right)\cdot\left(+7\right)$
$2x^4-9x^2+5x^2+13x-3\:entre\:x+1$
$\frac{\sin\:\left(\sqrt{19}t\right)}{\sqrt{19}}+\:\cos\:\left(\sqrt{19}t\right)$
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